0.5m v^2 = mgh. 0.5 *16*16 = 9.8* h. so h = 1.33 m . SECOND PART. as the motion is kinetic motion in one dimensional. so, time to go maximum height , t1. as, v= u+at here a= -g because acceleration is acceleration due to gravity which always act downward. v=0 at maximum height. so t1 = u/g = 16/9.8 = 1.63 s .
A baseball is hit nearly straight up into the air with a speed of 24 m/s . A) How high does it go? B) How long is it in the air ?, Physics (7th Edition) Edit edition Solutions for Chapter 2 Problem 42P: (II) A baseball is hit almost straight up into the air with a speed of 25 m/s . Estimate (a) how high it goes, (b) how long it is in the air . (c) What factors make this an estimate?.
11/9/2018 · (a) How high does it go? in meters (b) How long is it in the air ? in seconds please and thank you!-v² = 2gh 42² = 2gh h = 90 m t = ?(2h/g) = 4.29 s -I dont know A baseball is hit nearly straight up into the air with a speed of 42 m/s .
10/31/2018 · We will use 0 as the final velocity, since the ball will stop moving upwards when it is the highest. We will use -9.8 since that is the acceleration due to gravity and we will use 22m/ s as V? since that is the starting velocity. So, the ball will go 24.69 meters up
